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[BriskAttivo]

I had to do this for my Physical Science class. I thought it was funny, because it's completely overcomplicating answering the phone. (I did all this work below.) By the way, what's new with everybody?

The Amount of Work Required to Answer a Telephone
by Brisk Attivo

Materials: Tape measure. Digital weight scale. Calculator. Regular deskset telephone.

This experiment was designated to determine the work required to answer a ringing a telephone on the floor (which is where I have my telephone), while sitting in my desk. I first disconnected the handset and placed it on the digital scale. The handset weighed 9 ounces. I converted that to kilograms: 0.25515 with the ratio of 28.35 g/1 oz. I then measured the distance from telephone to my face. My tape measure read 2 feet 7 inches. I converted that to meters. .0254 m/1 in. The distance was .7878 meters.

m = .25515 kg
g = 9.8 m/s^2
w = ?

w = mg

= (.25515 kg)( 9.8 m/s^2)
= (.25515 x 9.8) kg x m/s^2
= 2.50047 kg*m/s^2
w = 2.50047N


F = 2.50047N
d = .0254 m
W (work) = ?

W = Fd

= (2.50047)(.0254 m)
= (2.50047 x .0254)(N*m)
W = 0.063511938J (joules)

Conclusion: The projected amount of work required to answer my telephone from these calculations should be 0.063511938J by calculating the force times the distance. The distance from my phone would be variable of course, but sitting up right, the distance should be about the same on average.

[phreakblaze]

well, thats too much work for me, looks like i'l have to make an auto phone answerer.