5 replies to this topic

[AlexZ]

Create a program in what language you want, which create this triangle of number :

1
2 3
4 5 6
7 8 9 10
11 12 13 14 15

If you haven't understood the problem, you can follow the explaination on wikipedia of this particular triangle!!!
Here i link my solution, don't look at that before you've written yours program!!

Edited by AlexZ, 08 March 2010 - 08:49 AM.

[Ouroboros]

Heres my solution in python

Spoiler

def floyd(n):
	count = 1
	string = ""
	for i in range(1,n+2):
		for j in range(1,i):
			string = string + " " + str(count)
			count = count + 1
		print(string)
		string = ""

[n3xg3n]

Ruby solution

Spoiler

#!/usr/bin/ruby -w
# Floyd's Triangle

class FloydsTriangle
    def self.generate(max=15)
        line = 1
        added = 0
        triangle = ""

        for n in 1..max do
            triangle += "#{n.to_s} "
            added += 1

            if added == line
                triangle += "\n"
                added = 0
                line += 1
            end
        end

        triangle
    end

    def self.print(max=15)
        puts generate(max)
    end
end

if ARGV[0].to_i > 0
    FloydsTriangle.print(ARGV[0].to_i)
else
    FloydsTriangle.print
end

[PurpleJesus]

How did I miss this one??

Here's mine in C

Spoiler

#include<stdio.h>
#define MAX 15
int main (void)
{
	int x =0;  //thought "int x,y,z = 0" would initalize all three to zero...  but no...  it's not happening"
	int y =0;
	int z= 0;
	while (x++ < MAX)
	{
		printf("%2i ",x);
		if (++y > z)
		{
			printf("\n");
			z++;
			y = 0;
		}
	}
return 0;
}

[Lord Wud]

Heres my solution in python

Spoiler

def floyd(n):
	count = 1
	string = ""
	for i in range(1,n+2):
		for j in range(1,i):
			string = string + " " + str(count)
			count = count + 1
		print(string)
		string = ""

This is much better then mine, but here is how i did it.

Spoiler

def floydtriangle(begin,end):
  maxwidth = len(str(end))
  counter = 0
  output = ""
  next = 0
  for num in range(begin, end):
    if next == 0:
      output = output + str(num) + '\n'
      counter = counter + 1
      next = counter
    else:
      pad = maxwidth - len(str(num))
      pad = pad * " "
      pad = str(pad) + " "
      output = output + str(num) + pad
      next = next -1
  return output
def main():
  print floydtriangle(1,16)
  
if __name__ == '__main__':
  main()

Edited by Lord Wud, 13 September 2010 - 02:09 PM.

[heisenbug]

Perl solution

Spoiler

#!/usr/bin/perl
$number=$loopcount=1;
while (1) {
     for ($i=0;$i<$loopcount;$i++) {print $number++ . " ";}
     print "\n";
     $loopcount++;	
}